These two segments (DG and EH) should come out to be of equal distance.

Question

The coordinates of D are (-2h, 0) and G are (h,k).
Using the distance formula I got the distance of DG to be the square root of 3h squared + k squared.
Using the distance formula I got the distance of EH to be -3h squared + k squared.
I know the two distances should be equal. I don't know why the second segment is coming out with that negative 3. I must have made a mistake somewhere... please help.

Answer 1

You did not state the coordinates of E and H.

Answer 2

how do i fid the surface are for this shape??? HELP!

Answer 3

oops.
E (2h, 0)
A (0, 2k)

Answer 4

oops again.
E (2h, 0)
H (-h, k)

Answer 5

EH = √(2h-(-h))^2 + (0-k)^2)
= √(9h^2 + k^2)
which is the same as your other length

Answer 6

how could it be 9h squared? If you squared the 3? shouldn't that.. square be gone? I don't understand...