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Question

dy/dx-m2y=c1e^(m1x)
where c1,m1,m2 are constants and m1≠m2

the number like m1 m2 c1 are inform of base but I don't know how to write it

pls help me

Answer 1

again, use the integrating factor of e^(-m2 x)
That gives you
e^(-m2 x) y' - m2 e^(-m2 x) y = c1 e^(m1 x) e^(-m2 x)
(e^(-m2 x) y)' = c1 e^((m1-m2) x)
e^(-m2 x)y = c1/(m1-m2) e^((m1-m2)x) + k
y = c1/(m1-m2) e^(m1 x) + ke^(m2 x)