There were 52 books in a shop. Some of these books were sold for K5 each and the remainder were sold for K6 each. The total amount of money received for the sale of these books was K288. How much of the K6 books were sold

Answer 1

Let's define the number of books sold for K5 as \( x \) and the number of books sold for K6 as \( y \).

We know from the problem that:

1. The total number of books is 52: \[ x + y = 52 \]

2. The total revenue from the sales is K288: \[ 5x + 6y = 288 \]

Now, we can use the first equation to express \( x \) in terms of \( y \): \[ x = 52 - y \]

Next, substitute \( x \) into the second equation: \[ 5(52 - y) + 6y = 288 \]

Distributing the 5 gives us: \[ 260 - 5y + 6y = 288 \]

Combine the \( y \) terms: \[ 260 + y = 288 \]

Now, solve for \( y \): \[ y = 288 - 260 \] \[ y = 28 \]

Now that we have \( y \), the number of K6 books sold, we can find \( x \): \[ x = 52 - y = 52 - 28 = 24 \]

To summarize, the number of K6 books sold is \( \boxed{28} \).