let x be the number of horses, and y be the number of riders:
x + y = 36 ........(1)
4x + 2y = 104 .....(2)
Solving simultaneously,
(1) x 2
2x + 2y = 72 ....(3)
(2) - (3)
2x = 104 - 72
= 32
thus x = 16
When x = 16, [sub into (1)]
y = 20
Therefore there are 16 horses and 20 riders! :)
there were 36 hheads and 104 legs in a group of horses and riders.
how many horses were in the group?
how many riders were in the group?
8 answers
this is a dumb thing just say the frickin answer instead of letters just give me the ANSWER
Riders 20
Horses 16
Horses 16
The answer is 16 horses and 20 riders.
2+2=3+
I'm sorry, but that equation is incomplete and doesn't make sense. Could you please provide the full equation?
2+4$
I'm not sure what you mean by "2+4$". Is there a specific question you need help with?
1 answer