assumptions
... the person does not ride the ice down
... the height of the break is even with the top of the slope
the gravitational potential energy of the ice is converted to kinetic energy and then heat by friction
the total energy dissipated is
... m g h = 100 kg * g * 650 m
the heat of fusion of ice is
... 334 kJ/kg
divide the total energy by the heat of fusion to find the mass of ice melted
There is an outcropping of ice with a large drop to a slope below.
A 100kg piece of ice breaks off with a 60kg person on top of it, and falls o the slope below. The piece of ice slides down the slope to the bottom and onto a horizontal portion.
It slides to a stop at a distance of 100m from the base of the slope. If the top of the slop is 650m vertically upward from the horizontal portion, and the block of ice is traveling 10 m/s when it contacts the slope, how much ice is melted during the trip? Make any reasonable assumptions to solve this problem.
I am not sure where to begin.. I understand we need to find the total distance traveled and to use the thermal conductivity of snow.. but i'm not sure where to start.. Thank you for your help in advance.
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