There is a square whose vertices lie on a unit circle. Point P lies on the terminal arm of an angle in standard position, P(0.3420, 0.9397)

Question

how do you find the degrees of P?

Answer 1

since it is a unit circle, that is the radius is 1, then P can be written as (cosß,sinß)
then cosß = .3420
then angle ß = 70º

notice you would get the same if you took
sin ß = .9397
ß = 70º and notice that

.3420^2 + .9397^2 = 1

Answer 2

thanks