I do not understand your formula.
because the distance from the rod is much less than the rod length, assume it is an infinte rod.
E= 2k*lambda/r
r will be the radius of the rod plus the distance from the surface. r=0.0104m
lamda is 2uC/.5 micro coulombs/meter.
www.phys.uri.edu/~gerhard/PHY204/tsl31.pdf -
There is a rod that is 50cm long and has a radius of 1cm that carries a charge of 2uC distributed uniformly over its length. What would be the value of the magnitude of the electric field. (a) 4.0 mm from the rod surface, not either end
So far I got E1/4density-2pie0r or
E= 2(9.10^9)(8*10^-6) what do i do after that?
1 answer
1 answer