No, I can not explain that because I agree with you
either by side angle side or as you said by the angles
There is a parallelogram labeled (from left to right on the top) A - B
(from left to right on the bottom) D - E
There is a line that connects A to the opposite side E, and a line that connects B to the opposite side D. The intersection of the lines is labeled C (in the middle). AB is parallel to DE, and AD is parallel to BE. The questions asks if triangle ACD and BCE are similar and I thought "Yes," but the answer is "No" and I thought they would be because Angle ACD is equal to BCE because of the vertical angles theorem and Angle DAC is congruent to Angle CEB by Alternate Interior Angles Theorem. Can you explain why they wouldn't be similar?
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