There is a graph of f(x) and g(x). They intersect at two points. Michael says that the values of (x)=g(x) are the ordered pairs where the functions intersect. Find Michael's mistake and explain what he misunderstood.
Eric isn't sure why a solution to a system of inequalities cannot be on a dotted line of a graph. Explain why points on the dotted line of an inequality can't be in the solution set.
2 answers
*sorry, Michaels problem was supposed to say f(x)=g(x)
Huh? y = f(x) is one function
y = g(x) is another function
They , f and g, are the same for two values of x
Those points are where y = f(of that x) and same y = g(of that same x)
so at those points
y = f(x) = g(x)
and the points,( x,y) are (x ,f(x)) and (x,g(x)) and f(x)=g(x)
y = g(x) is another function
They , f and g, are the same for two values of x
Those points are where y = f(of that x) and same y = g(of that same x)
so at those points
y = f(x) = g(x)
and the points,( x,y) are (x ,f(x)) and (x,g(x)) and f(x)=g(x)