There are two types of tickets to attend an awards dinner silver and gold. The gold tickets are $8 more than the silver. If Patrick bought 10 tickets at each level and spent a total of $140, find the price of each ticket.

Answer 1

Let's assume the price of a silver ticket is $x.
Therefore, the price of a gold ticket is $x + $8.

Patrick bought 10 silver tickets at a cost of 10 * $x = $10x.
He also bought 10 gold tickets at a cost of 10 * ($x + $8) = $10x + $80.

The total cost of the tickets is $10x + $10x + $80 = $140.

Combining like terms, we get $20x + $80 = $140.

Subtracting $80 from both sides of the equation, we get $20x = $60.

Dividing both sides of the equation by $20, we get x = $3.

Therefore, the price of a silver ticket is $3.
And the price of a gold ticket is $3 + $8 = $11. Answer: \boxed{3,11}.