There are three choices of fruit are bananas, pears, and oranges. If the probability of getting a banana is 5/12 and the probability of getting a pear is 1/6, what is the probability of getting an orange?

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Answer 1

The sum of the probabilities of all three choices must equal 1. Since the probability of getting a banana is 5/12 and the probability of getting a pear is 1/6, the probability of getting an orange can be calculated as follows:

Probability of getting an orange = 1 - (Probability of getting a banana + Probability of getting a pear)
Probability of getting an orange = 1 - (5/12 + 1/6)
Probability of getting an orange = 1 - (10/12 + 2/12)
Probability of getting an orange = 1 - 12/12
Probability of getting an orange = 0

Therefore, the probability of getting an orange is 0.