There are three choices of fruit are bananas, pears, and oranges. If the probability of getting a banana is 5/12 and the probability of getting a pear is 1/6, what is the probability of getting an orange?

Question

Responses
A Image with alt text:
B Image with alt text:
C Image with alt text:
D

Answer 1

The probability of getting an orange can be determined by subtracting the probabilities of getting a banana and a pear from 1.

Probability of getting an orange = 1 - probability of getting a banana - probability of getting a pear
Probability of getting an orange = 1 - 5/12 - 1/6
Probability of getting an orange = 12/12 - 5/12 - 2/12
Probability of getting an orange = 5/12

Therefore, the probability of getting an orange is 5/12.

So the correct response is:
D. 5/12