There are three choices of fruit are bananas, pears, and oranges. If the probability of getting a banana is 5/12 and the probability of getting a pear is 1/6, what is the probability of getting an orange?

Question

5/12

1/2

1/3

1/12

Answer 1

The total probability of getting any of the three fruits must add up to 1.

Therefore, let x be the probability of getting an orange.

5/12 (Banana probability) + 1/6 (Pear probability) + x = 1
5/12 + 1/6 + x = 1
(x = 1 - 5/12 - 1/6)
(x = 12/12 - 5/12 - 2/12)
(x = 5/12)

So, the probability of getting an orange is 5/12.