There must be problems on extrema. The extrema occur where f' = 0. Here,
f(x) = x^(1/3)
f'(x) = 1/3 x^(-2/3)
f'(x) is never zero anywhere, especially in this interval.
So, we just want the maximum and minimum values attained on the interval. Note that f' > 0 everywhere, so it is strictly increasing. That means
f(-3) < f(64)
f(-3) = -∛3
f(64) = 4
So, those are the extrema on this interval.
Looks like (A) to me.
there are no examples of this type of problem in my book so if you could help walk me through it - that would be extremely helpful. thanks ahead of time.
Find the extreme values of the function on the interval and where they occur.
4) F(x)=³√(x); -3</=x</=64
A. Maximum at (64, 4), and minimum at (-3, ³√-3)
B. Maximum at (-64, 4), and minimum at (0,0)
C. Maximum at (0,0), and minimum at (64,4)
D. Maximum at (64,4), and minimum at (-64,-4).
Thanks again.
2 answers
Thanks! I'll go with that and then if I do get it wrong - I'll ask for an explanation as to why from my teacher. Thanks for explaining it too :) It's starting to make more sense.