There are a total of 30 gum balls in the machine.
The probability of getting a green gum ball on the first draw is 5/30.
After one green gum ball has been drawn, there are 29 gum balls left in the machine, including 8 yellow gum balls. So the probability of drawing a yellow gum ball after drawing a green gum ball is 8/29.
The probability of getting a green gum ball first and then a yellow gum ball is the product of these two probabilities: 5/30 * 8/29 = 40/870.
So the answer is option D, start fraction 40 over 870 end fraction.
There are 9 red gum balls, 5 green gum balls, 8 yellow gum balls, and 8 blue gum balls in a machine. Find P(green, then yellow).
A. start fraction 40 over 900 end fraction
B. The term shows 5 over 30.
C. The term shows 8 over 30.
D. start fraction 40 over 870 end fraction
1 answer