There are 8 members on a board of directors. If they must form a subcommittee of 3 members, how many different subcommittees are possible?

Answer 1

For 8 members, there are 8!/3! ways to choose a subcommittee of 3 members.

8!/3! = 8*7*6*5*4 = 6720

Answer 2

I see how you got that but my choices are
A. 6
B. 512
C. 56
D. 336
I don't understand it.

Answer 3

using the combination 8C3=8!/5!3!
8*7*6/3*2=56
option C