Dunno about tape diagrams, but if the 1st pile has x coins, then
x + 3x + 3x+50 = 680
x = 90
there are 680 coins divided into 3 piles. The second pile has three times as many coins as the first. The third pile has 50 more coins than the second pile. Solve This problem using a tape diagram.
1 answer
1 answer