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There are 6 television shows coming on this week that Gabe wants to watch. They all come on at different times, but his mom wil...Asked by idk
There are 6 television shows coming on this week that Gabe wants to watch. They all come on at different times, but his mom will only let him watch 4 shows a week. How many different combinations of shows can Gabe choose to watch? (1 point) Responses 15 15 30 30 45 45 60
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Answered by
GPT-4o mini
To find out how many different combinations of shows Gabe can choose to watch, we need to calculate the number of ways to choose 4 shows from the 6 available shows. This is a combinations problem and can be solved using the binomial coefficient formula:
\[
\binom{n}{r} = \frac{n!}{r!(n-r)!}
\]
where \(n\) is the total number of items (shows), and \(r\) is the number of items to choose.
In this case, \(n = 6\) and \(r = 4\). Therefore, we need to calculate:
\[
\binom{6}{4} = \frac{6!}{4!(6-4)!} = \frac{6!}{4! \cdot 2!}
\]
Calculating the factorial values:
- \(6! = 6 \times 5 \times 4! = 720\)
- \(4! = 24\)
- \(2! = 2\)
Now plug these back into the equation:
\[
\binom{6}{4} = \frac{720}{24 \cdot 2} = \frac{720}{48} = 15
\]
Thus, the number of different combinations of shows that Gabe can choose to watch is:
\[
\boxed{15}
\]
\[
\binom{n}{r} = \frac{n!}{r!(n-r)!}
\]
where \(n\) is the total number of items (shows), and \(r\) is the number of items to choose.
In this case, \(n = 6\) and \(r = 4\). Therefore, we need to calculate:
\[
\binom{6}{4} = \frac{6!}{4!(6-4)!} = \frac{6!}{4! \cdot 2!}
\]
Calculating the factorial values:
- \(6! = 6 \times 5 \times 4! = 720\)
- \(4! = 24\)
- \(2! = 2\)
Now plug these back into the equation:
\[
\binom{6}{4} = \frac{720}{24 \cdot 2} = \frac{720}{48} = 15
\]
Thus, the number of different combinations of shows that Gabe can choose to watch is:
\[
\boxed{15}
\]
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