there are 6^3 ways to travel on the three days
walking on one day leaves 5^2 options for the other two
p = (3 * 5^2) / (6^3)
There are 6 methods of travel (walk,run,unicycle,bicycle,scooter,car).
For three days, Max decides that he wants to randomly select his method of travel taking him to work.
What is the probability that exactly one of the three days, Max walks to work?
3 answers
Thanks a lot Scott!!
Note that this is also 3(1/6)(5/6)^2