your first card could be 52 different ones, leaving 51 different ones to draw for you second, then 50 for the third and 49 for the fourth, and finally 48 for the last.
so what is 52(51)(50)(49)(48)
= ...
There are 52 cards in a standard deck. if you draw a card, do not replace it, and then draw 4 more cards, one at a time without replacement, how many possible outcomes are there?
I don't get it...Thank you
1 answer