There are 5 red socks, 2 white socks, and 3 blue socks in a basket. What is the probability of selecting one red sock from the basket, then selecting a second red sock from the basket without replacing the first? (1 point) Responses 29 2 9 790 7 90 15 1 5 9100

Answer 1

To find the probability of selecting one red sock from the basket, and then selecting a second red sock without replacing the first, we follow these steps:

1. Calculate the total number of socks:

   • Red socks: 5
   • White socks: 2
   • Blue socks: 3
   • Total socks = 5 (red) + 2 (white) + 3 (blue) = 10 socks.

2. Find the probability of selecting the first red sock:

   • Probability of selecting the first red sock = Number of red socks / Total number of socks = 5/10 = 1/2.

3. Find the probability of selecting the second red sock after the first red sock has been removed:

   • After removing one red sock, there are now 4 red socks left out of a total of 9 socks (since one sock has been removed).
   • Probability of selecting the second red sock = Number of remaining red socks / Total remaining socks = 4/9.

4. Calculate the combined probability:

   • Combined probability = (Probability of first red sock) × (Probability of second red sock) = (5/10) × (4/9) = (1/2) × (4/9) = 4/18 = 2/9.

Thus, the probability of selecting one red sock and then a second red sock (without replacement) is \(\frac{2}{9}\).

The correct response is 2/9.