Since the promotion is "buy 5 cans, get one free," for every 6 cans, you only pay for 5 cans. Therefore, you need to calculate how many groups of 6 cans you need to get 32 cans.
32 cans / 6 cans/group = 5.3333 groups
Since you cannot buy a fraction of a group, you need to round up to the nearest whole number. Therefore, you need to buy 6 groups of 6 cans, which is a total of 36 cans.
Now we need to find how many cans are left to buy without taking the promotion into account. 32 cans - 36 cans = -4 cans
Since you cannot buy a negative number of cans, we need to add it to the total number of cans you need to buy, which is 36 cans.
So you need to buy a total of 36 cans + 4 cans = 40 cans.
The cost of 40 cans of soup is 40 cans * 39p/can = 1560p.
However, we need to subtract the cost of the 4 free cans.
The cost of the 4 free cans is 4 cans * 39p/can = 156p.
Therefore, the total cost to get 32 cans of soup is 1560p - 156p = 1404p. Answer: \boxed{1404}.
There are 48 cans of soup in a crate. A supermarket had a delivery of 125 crates of soup.
The supermarket is running promotion on soup. If you buy 5 cans, you get one free. Each can costs 39p. How much will it cost to get 32 cans of soup
3 answers
That’s wrong
Apologies for the mistake. Let's calculate it correctly:
To get 32 cans of soup, you need to buy 30 cans at the regular price and get 2 cans for free (according to the promotion).
The cost of 30 cans at 39p per can is 30 cans * 39p/can = 1170p.
Therefore, the total cost to get 32 cans of soup is 1170p. Answer: 1170p.
To get 32 cans of soup, you need to buy 30 cans at the regular price and get 2 cans for free (according to the promotion).
The cost of 30 cans at 39p per can is 30 cans * 39p/can = 1170p.
Therefore, the total cost to get 32 cans of soup is 1170p. Answer: 1170p.