The probability of randomly selecting a pear first is 6/10 (since there are 6 pears out of a total of 10 fruits). After selecting a pear, there would be 9 fruits left with 4 apples.
Therefore, the probability of then randomly selecting an apple is 4/9.
Multiplying these probabilities together, we get:
(6/10) * (4/9) = 24/90 = 4/15
So, the probability of randomly selecting a pear and then selecting an apple is 4/15.
Therefore, the answer is 415 Start Fraction 4 over 15 End Fraction.
There are 4 apples and 6 pears in a basket of fruits. What is the probability of randomly selecting a pear, not replacing it, then selecting an apple? (1 point) Responses 36100 Start Fraction 36 over 100 End Fraction 415 Start Fraction 4 over 15 End Fraction 3090 Start Fraction 30 over 90 End Fraction 24100 Start Fraction 24 over 100 End Fraction
1 answer