To find the equations of the lines representing the two racers based on the points you've provided, we'll first determine the slopes and then the equations of the lines using the slope-intercept form \(y = mx + b\) where \(m\) is the slope and \(b\) is the y-intercept.
Racer One:
The points given are (0, 8), (4, 9), and (8, 10).
To find the slope \(m\) between two points, we can use the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Let's find the slope using the first two points (0, 8) and (4, 9):
- \(x_1 = 0\), \(y_1 = 8\)
- \(x_2 = 4\), \(y_2 = 9\)
\[ m = \frac{9 - 8}{4 - 0} = \frac{1}{4} \]
Now using the slope and one of the points (0, 8) to determine \(b\):
Using the equation \(y = mx + b\): \[ 8 = \frac{1}{4}(0) + b \implies b = 8 \]
So the equation for Racer One is: \[ y = \frac{1}{4}x + 8 \]
Racer Two:
The points given are (0, 6), (2, 7), (4, 8), (6, 9), and (8, 10).
Using the first two points (0, 6) and (2, 7) to find the slope:
\[ m = \frac{7 - 6}{2 - 0} = \frac{1}{2} \]
Now to determine \(b\) using the point (0, 6): \[ 6 = \frac{1}{2}(0) + b \implies b = 6 \]
So the equation for Racer Two is: \[ y = \frac{1}{2}x + 6 \]
Summary:
- Racer One: \(y = \frac{1}{4}x + 8\)
- Racer Two: \(y = \frac{1}{2}x + 6\)