First, let's find the probability of selecting a pear first:
The probability of selecting a pear on the first pick is 4/7 since there are 4 pears out of a total of 7 fruits.
Next, after selecting a pear, we are left with 3 apples, 3 pears, and 1 pear (because we did not replace it). So, the probability of selecting an apple on the second pick is 3/6 or 1/2.
Therefore, the probability of selecting a pear first, NOT replacing it, then selecting an apple is:
(4/7) * (3/6) = (4/7) * (1/2) = 4/14 = 2/7
So, the probability of randomly selecting a pear, NOT replacing it, then selecting an apple is 2/7.
There are 3 apples and 4 pears in a basket of fruit. What is the probability of randomly selecting a pear, NOT replacing it, then selecting an apple?
Show ALL work and don't forget to simplify.
1 answer