There are 3 airports, A , E and G. G is 200km from A.E is 160 km from A From G the bearing of A is 052 degrees. From A the bearing of E is 216 degrees. What's the distance between A and G?

Question

360- 216 = 144
144-52 = 128
144-128 = 16

a^2 = b^2+c^2-(2*b*c)*cos(A)
a^2 = 160^2 + 200^2 - ( 2 * 160 * 200) * (cos 16)
a^2 = 4079.25...
a = 63.9 km <--- ?

Answer 1

Looks good to me.

Answer 2

Thank you