Let the price of the silver ticket be \( x \). Then, the price of the gold ticket would be \( x + 8 \).
Patrick bought 10 silver tickets and 10 gold tickets, spending a total of $140. We can set up the following equation based on this information:
\[ 10x + 10(x + 8) = 140 \]
Now, simplify the equation:
\[ 10x + 10x + 80 = 140 \] \[ 20x + 80 = 140 \]
Subtract 80 from both sides:
\[ 20x = 60 \]
Now, divide by 20:
\[ x = 3 \]
So, the price of the silver ticket is \( x = 3 \).
To find the price of the gold ticket:
\[ x + 8 = 3 + 8 = 11 \]
Thus, the prices of the tickets are:
- Silver ticket: $3
- Gold ticket: $11