There are ${12 \choose 3} = 220$ possible committees of 3 people that can be formed from a group of 12.

Answer 1

This is calculated using the combination formula, which is ${n \choose k} = \frac{n!}{k!(n-k)!}$ where n is the total number of items to choose from and k is the number of items to choose. In this case, there are 12 people to choose from and we want to choose 3 people, so ${12 \choose 3} = \frac{12!}{3!(12-3)!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220$.