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There are 12 card numbered 1 to 12 in a box. If tow cards are selected, what is the probability that the sum is odd (I) with replacement (II) without replacement.

SOLUTIONS (1/4,6/11)
HOW I CAN SOLVE WITH REPLACEMENT.
Knowing that
Sample space (S) = 12C2=66
And there are 6 odd (O)& 6 even (E)
So, probability without replacement= (6C1*6c1)/66 =6/11
So how to solve this problem with replacement. Thanks

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