The frequency of the homozygous recessive condition would be 4%, so the frequency of the recessive allele (q^2) would be the square root of 4%, which is 0.2 or 20%.
Since q^2 = 0.04, q = 0.2
Now, we can calculate the frequency of the dominant allele (p) by subtracting q from 1:
p = 1 - q
p = 1 - 0.2
p = 0.8 or 80%
Now, we can calculate the frequency of heterozygous individuals (2pq) using the formula:
2pq = 2 * 0.8 * 0.2
2pq = 0.32 or 32%
Therefore, the correct answer is c) 32%.
there are 100 students in a class. Ninety-six did well in the course whereas four blew it totally and received
a grade of F. Sorry. In the highly unlikely event that these traits are genetic rather than environmental,
if these traits involve dominant and recessive alleles, and if the four (4%) represent the frequency of the
homozygous recessive condition, please calculate the frequency of heterozygous individuals (2pq).
a
16%
b
29%
c
32%
d
57%
1 answer