Since the order in which the students are chosen does not matter, we can use combinations to solve this problem. The number of ways to choose 3 students out of 10 is given by the combination formula:
${{10}\choose{3}}=\frac{10!}{3!(10-3)!}=\frac{10!}{3!7!}=\frac{10\times9\times8}{3\times2\times1}=120$.
Therefore, there are $\boxed{120}$ ways to choose the students.
There are 10 students in a class. The teacher chooses 3 students to go to the library. The order in which they are chosen does not matter. How many ways are there to choose the students?
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