Let's use algebra to solve this problem.
Let x be the number of pets Jessie has.
Since Theodora has 2 times as many pets as Jessie, she has 2x pets.
Since Elizabeth has 4 more pets than Jessie, she has x + 4 pets.
Together, the girls have 16 pets.
So, x + 2x + x + 4 = 16
Combining like terms, we get 4x + 4 = 16
Subtracting 4 from both sides, we get 4x = 12
Dividing by 4, we get x = 3
So, Jessie has 3 pets.
Theodora has 2(3) = 6 pets.
Elizabeth has 3 + 4 = 7 pets.
Therefore, the answer is Theodora: 6, Elizabeth: 7, Jessie: 3. The correct answer is C.
Theodora, Elizabeth, and Jessie each have some pets. Theodora has 2 times as many pets as Jessie. Elizabeth has 4 more pets than Jessie. Together the girls have 16 pets. How many pets does each girl have?
A
Theodora: 10, Elizabeth: 9, Jessie: 5
B
Theodora: 3, Elizabeth: 7, Jessie: 6
C
Theodora: 6, Elizabeth: 7, Jessie: 3
D
Theodora: 8, Elizabeth: 8, Jessie: 4
1 answer
1 answer