After Theo added 9 to both sides, he simplified the equation to \((x + 2)^2 = 4\). When he takes the square root of both sides, we have:
\[ \sqrt{(x + 2)^2} = \sqrt{4} \]
This results in:
\[ x + 2 = \pm 2 \]
So the correct resulting equation from that step is:
x + 2 = ±2.