Given the equation y = 4(x + 2)
When x = -1:
y = 4(-1 + 2)
y = 4(1)
y = 4
Therefore, when x = -1, y = 4.
When x = 0:
y = 4(0 + 2)
y = 4(2)
y = 8
Therefore, when x = 0, y = 8.
When x = 1:
y = 4(1 + 2)
y = 4(3)
y = 12
Therefore, when x = 1, y = 12.
Then find the value of y for each value of x. (Type an integer or as a simplified fraction) (3 points)
When x=−1 , the value of y is
When x=0 , the value of y is
When x=1 , the value of y is
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