Then, determine the final volume needed to dilute 20.0 ml of 1.00 M NaOH to 0.25 M. Next, find the volume of water which needs to be added. Finally, determine the moles and the mass in grams of NaOH in the solutions.
Final volume formula is Vf= mi/mf
20 ml=1.00/0.25=80 ml 80-20= 60 ml Vf-vi to get water
Is this right? I am having trouble converting
4 answers
Looks ok to me for the dilution but mols and grams you didn't do.
Do I use the 60 ml to convert to mols and grams ?
60ml(0.25/.06) 0.150 mols how would I get grams
For the 20 mL of 1.00 M NaOH you have mols = M x L = 0.020 x 1.00 = 0.020 mols and grams = mols x molar mass.
diluted solution (0.25M) you have the same, don't you? You added 20 mL of 1.00 M NaOH to 60 mL H2O so you added 0.02 mols for that dilution. Yes the concentration changed because you put that same 0.02 mols in a larger volume of 80 mL and 0.02mols/0.08L = 0.25M. Of course grams is same also.
diluted solution (0.25M) you have the same, don't you? You added 20 mL of 1.00 M NaOH to 60 mL H2O so you added 0.02 mols for that dilution. Yes the concentration changed because you put that same 0.02 mols in a larger volume of 80 mL and 0.02mols/0.08L = 0.25M. Of course grams is same also.