The chipping of the Zn electrode in ZnSO4 solution indicates that the Zn electrode is undergoing oxidation and giving off electrons, so it is acting as an anode. The reaction occurring at the anode can be represented as:
Zn(s) ā Zn2+(aq) + 2eā
This reaction releases electrons from the Zn electrode, making it an anode.
The Zn electrode is chipped in a solution containing ZnSO_4 and gives off electrons. It is therefore?
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