The x-value of a solution to the system y=2x^2+8 and 3x-y=-3 is

Answer 1

using substitution,
3x-(2x^2+8) = -3
2x^2 - 3x + 5 = 0
There is no real solution.
See the graphs at

https://www.wolframalpha.com/input/?i=plot+y%3D2x%5E2%2B8+%2C+3x-y%3D-3