The magnitude is obtained by taking the square root of the sum of squares of the components.
A vector with 3 and 4 units as the x- and y-components will have a magnitude of √(3²+4²)=5 units.
The angle of the vector measured from the x-axis is given by tan-1(y-component/x-component).
Be careful with the quadrant, as the tan-1 function usually ranges only from -π/2 to π/2.
The x-component of vector A is -25.0 m and the y-component is +40.0 m.
a) what is the magnitude of vector A?
b) What is the angle between the direction of vector A and the positive direction of vector x?
can you please help me with the steps to accomplishing these?
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