Can someone please explain?
a. The formula for exponential growth is P(t) = P0*e^(rt), where P0 is the initial population, r is the growth rate, and t is the time. In this case, P0 = 5.3 and r = 0.02. To find t0, we need to solve for t when P(t) = 2P0. This gives us t0 = ln(2)/(0.02) = 34.53 yr.
b. To find the population with a growth rate of 1.2%, we can use the same formula, but with r = 0.012. This gives us P(t) = 5.3*e^(0.012*t). To find the population after 34.53 years, we plug in t = 34.53 and get P(34.53) = 5.3*e^(0.412) = 10.6 billion people.
The world population at the beginning of 1990 was 5.3 billion. Assume that the population continues to grow at the rate of approximately 2%/year and find the function Q(t) that expresses the world population (in billions) as a function of time t (in years), with t = 0 corresponding to the beginning of 1990. (Round your answers to two decimal places.)
(a). If the world population continues to grow at approximately 2%/year, find the length of time t0 required for the population to double in size.
t0=____yr
(b). Using the time t0 found in part (a), what would be the world population if the growth rate were reduced to 1.2%/yr?
____ billion people
I don't understand how to set this problem up correctly.
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