Asked by Dave

The worker pushes with a force of 10 N that points downward at an angle of 45° below the horizontal. What component of the force moves the crate forward?

I do not know how to set up this problem, so any help would be appreciated.
Answered by Scott
the component of the force that moves the crate (horizontal) is...the applied force, multiplied by the sine of the angle to the component

10N * sin(45º)

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