the work function for metallic Caesium is 2.14 eV. Calculate the kinetic energy and the speed of the electrons ejected by light of wavelength 700 nm

Answer 1

The photon energy is h*c/(wavelength) = 2.84*10^-19 J = 1.77 eV

Unless I made an error somewhere, there is not enough energy in a photon of that wavelength to eject a photoelectron.

Answer 2

2.8397j