The wings of a certain airplane have a total surface area of 100 m^2. At a particular speed, the difference in air pressure below and above the wings is 4% of atmospheric pressure. Show that the lift on the airplane is 4 x 10^5n

Answer 1

Given:
Total surface area of the wings (A) = 100 m^2
Difference in air pressure (ΔP) = 4% of atmospheric pressure

We know that the lift force (L) on an airplane is given by the formula:
L = A * ΔP

First, let's calculate the atmospheric pressure:
Let atmospheric pressure be P
4% of atmospheric pressure = 0.04 * P

Now, the lift force (L) can be calculated using the given values:
L = A * ΔP
L = 100 * 0.04 * P
L = 4 * P

Given that the lift force is 4 x 10^5N, we have:
4P = 4 * 10^5
P = 10^5 N/m^2

Therefore, the lift on the airplane is 4 x 10^5N.