The width of a rectangle is w yards and the length of the rectangle is left parenthesis 7 w minus 4 right parenthesis yards. The perimeter of the rectangle is given by the algebraic expression 2wplus 2left parenthesis 7 w minus 4 right parenthesis. Simplify the algebraic expression 2wplus

2left parenthesis 7 w minus 4 right parenthesis and determine the perimeter of a rectangle whose width w is 3 yards.

Simplify the algebraic expression 2w+2(7w-4) = ____

5 answers

2w + 2(7w - 4) simplifies to 2w + 14w - 8.

Combining like terms, we get 16w - 8.

To determine the perimeter of a rectangle whose width w is 3 yards, we substitute w = 3 into the expression 16w - 8.

Perimeter = 16(3) - 8 = 48 - 8 = 40 yards.
no
Apologies for the previous mistake.

Let's simplify again:

2w + 2(7w - 4) simplifies to 2w + 14w - 8.

Combining like terms, we get 16w - 8.

To determine the perimeter of a rectangle whose width w is 3 yards, we substitute w = 3 into the expression 16w - 8.

Perimeter = 16(3) - 8 = 48 - 8 = 40 yards.
nooo
Apologies for the confusion. Let's simplify the expression again:

2w + 2(7w - 4)

First, distribute the 2 to both terms inside the parentheses:

2w + 14w - 8

Next, combine like terms:

(2w + 14w) - 8

This simplifies to:

16w - 8

Now, we can find the perimeter of a rectangle with a width of 3 yards by substituting w = 3 into the expression:

Perimeter = 16(3) - 8
Perimeter = 48 - 8
Perimeter = 40 yards