the width of a rectangle is six less than the length the area of the rectangle is 58 square feet write and solve and equation to find the dimensions of the rectangle rounded to the nearest tenth

Answer 1

W=L-6
W*L=58

(L-6)*L=58
L^2-6L-58=0

Using the quadratic formula
L=(6+-sqrt(36+232))/2=11.2,5.2 rounded