The width of a rectangle is 6 centimeters less than the lenght. The perimeter is 64 centimeteres . would you please help me, answer these work. than you.
L = length
W = width
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eqn 1:
2L + 2W = perimeter = 64 cm
eqn 2:
W+6cm = L
Solve the two equations simultaneously for W and L.
Post your work if you get stuck.
Well I don't know How to get it if I have to multiply or od i 2L + 2w what do I do I' m sorry but have so much trouble do in these work
You need to read your text or your notes on how to solve simultaneous equations. Basically, you solve for L in terms of W to eliminate one of the unknowns, then solve for that unknown.
well i only have the the question and that it these is what is in the book . Two angles of a triangle are 40 degrees and 62 degrees; what is the third angle's measure?
the width of a rectangle is 6 centimeters than the length . the perimeter is 64 centimeters . zI soryy but that's all i have in my book.
2L + 2W = 64cm
W + 6cm = L
substitue the value of L back into the first formula.
2(W + 6cm)+ 2W = 64cm
2W + 12cm + 2W = 64cm
4W + 12cm = 64cm
4W = 64cm - 12cm
4W = 52cm
W = 52cm/4
W= 13cm
therefore L = W + 6cm
substitue the value of W into the equation above to find the value of L.
L = 13cm + 6cm
L = 19cm
2 answers