length = x
width = x-2
solve x(x-2) = 3 or
x^2 - 2x - 3 = 0
hint: it factors very easily
The width of a rectangle is 2 feet less that the length. The area is 3 feet^2. Find the length and width.
5 answers
Ok I think I am even more confused: its 3 feet^2
So is it x^2-2x-9=0
So is it x^2-2x-9=0
because if I use what you gave me would it be
(x-3)(x+1)
and then what would i do?
(x-3)(x+1)
and then what would i do?
huH?
length x width = area
x(x-2) = 3 ---- (it was given as 3 square units)
x^2 - 2x - 3 = 0
(x-3)(x+1) = 0
x = 3 or x=-1, the second answer is extraneous
check: x = 3 , so
length = 3
width = 3-2 = 1
area = 3x1 = 3
my answer checks!
length x width = area
x(x-2) = 3 ---- (it was given as 3 square units)
x^2 - 2x - 3 = 0
(x-3)(x+1) = 0
x = 3 or x=-1, the second answer is extraneous
check: x = 3 , so
length = 3
width = 3-2 = 1
area = 3x1 = 3
my answer checks!
Ok, so i did the problem right, but just was not sure what to do with them. sorry for the confusion...thanks for the help!