The wheels, axle, and handles of a wheelbarrow weigh 60.0 N. The center of gravity of the wheelbarrow alone is 0.600 m from the axel. The distance from the axle to the hands of the operator is 1.3 m. The force applied by the operator to the end of the handles is 250 newtons. The load chamber and contents is positioned 0.400 meters from the axle. What weight, in newton s, is the camber and its contents?
i don't even know where to begin..
1 answer
Start out by defining the rotational axis at the wheel since all of the distances from that point are given. Both the weight of the wheelbarrow and the weight of the load are acting upon the wheel in a clockwise direction, so they are negative. The force applied up is counterclockwise, so it is positive. Using sum of the torques, we get an equation like this: WL= (F*dF +W*dW)/dWL.
1 answer