The wheel is attached to an electric generator and the rotation rate drops from 290 to 230 in 3.5 . What is the average power output?
2 answers
units???
To start off, I will assume that 290 and 230 are in terms of rpm.
Pave=(Kf-Ki)/t
t=3.2
K=1/2*I(inertia)*w(omega)^2
Inertia of disc= 1/2*m*r^2
W must be in terms of rad/s, so multiply each rpm term by 2pi/30.
Kf-Ki= (1/2)*(1/2*m*r^2)*(Wf^2-Wi^2)
Divide Kf-Ki by t and you will get average power.
Pave=(Kf-Ki)/t
t=3.2
K=1/2*I(inertia)*w(omega)^2
Inertia of disc= 1/2*m*r^2
W must be in terms of rad/s, so multiply each rpm term by 2pi/30.
Kf-Ki= (1/2)*(1/2*m*r^2)*(Wf^2-Wi^2)
Divide Kf-Ki by t and you will get average power.
3 answers