The weights of the starting lineup of a football team are as follows (in pounds)

217 235 212 253 233 171 184 301 256 297 247 226 237 241 195 204 197 214 166 309 281 303 309 299
what’s the variance?

1 answer

To calculate the variance of the weights of the starting lineup of the football team, we can use the following steps:

  1. Calculate the mean (average) weight.
  2. Calculate the squared differences from the mean.
  3. Compute the average of those squared differences.

Step 1: Calculate the mean

First, we need to sum the weights and then divide by the number of weights.

Weights: \[ 217, 235, 212, 253, 233, 171, 184, 301, 256, 297, 247, 226, 237, 241, 195, 204, 197, 214, 166, 309, 281, 303, 309, 299 \] Total number of weights (n): 24

Sum of weights: \[ 217 + 235 + 212 + 253 + 233 + 171 + 184 + 301 + 256 + 297 + 247 + 226 + 237 + 241 + 195 + 204 + 197 + 214 + 166 + 309 + 281 + 303 + 309 + 299 = 6101 \]

Mean: \[ \text{Mean} = \frac{6101}{24} \approx 254.2083 \]

Step 2: Calculate squared differences from the mean

Next, we need to compute the squared difference for each weight from the mean.

\[ \begin{align*} (217 - 254.2083)^2 & \approx 1381.6486 \ (235 - 254.2083)^2 & \approx 374.0203 \ (212 - 254.2083)^2 & \approx 1774.6482 \ (253 - 254.2083)^2 & \approx 1.4465 \ (233 - 254.2083)^2 & \approx 447.0835 \ (171 - 254.2083)^2 & \approx 6863.6882 \ (184 - 254.2083)^2 & \approx 4908.9150 \ (301 - 254.2083)^2 & \approx 2209.9162 \ (256 - 254.2083)^2 & \approx 3.2220 \ (297 - 254.2083)^2 & \approx 1824.5521 \ (247 - 254.2083)^2 & \approx 51.0725 \ (226 - 254.2083)^2 & \approx 784.5158 \ (237 - 254.2083)^2 & \approx 293.3581 \ (241 - 254.2083)^2 & \approx 171.5444 \ (195 - 254.2083)^2 & \approx 3483.9126 \ (204 - 254.2083)^2 & \approx 2529.3782 \ (197 - 254.2083)^2 & \approx 3267.8660 \ (214 - 254.2083)^2 & \approx 1600.9668 \ (166 - 254.2083)^2 & \approx 7660.9675 \ (309 - 254.2083)^2 & \approx 3026.4139 \ (281 - 254.2083)^2 & \approx 710.5575 \ (303 - 254.2083)^2 & \approx 2392.4406 \ (309 - 254.2083)^2 & \approx 3026.4139 \ (299 - 254.2083)^2 & \approx 2010.1222 \ \end{align*} \]

Now we add all the squared differences together: \[ 1381.6486 + 374.0203 + 1774.6482 + 1.4465 + 447.0835 + 6863.6882 + 4908.9150 + 2209.9162 + 3.2220 + 1824.5521 + 51.0725 + 784.5158 + 293.3581 + 171.5444 + 3483.9126 + 2529.3782 + 3267.8660 + 1600.9668 + 7660.9675 + 3026.4139 + 710.5575 + 2392.4406 + 3026.4139 + 2010.1222 = 53639.816 \]

Step 3: Compute the variance

Since this is a sample from a population (the starting lineup), we will use the sample variance formula, which divides by (n - 1):

\[ \text{Variance} = \frac{53639.816}{24 - 1} = \frac{53639.816}{23} \approx 2332.1607 \]

Thus, the variance of the weights is approximately 2332.16 pounds².

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