The weight P is inversely proportional to the distance D, so we can set up the equation:
P = k/D
where k is the constant of proportionality.
Given that P = 8000/D, we can plug in P = 2000 and solve for D:
2000 = 8000/D
D = 8000/2000
D = 4 feet
Therefore, the distance between the supports needed to carry 2000 lb is 4 feet.
The weight P in pounds that a beam can safely carry is inversely proportional to the distance D in feet between the supports of the beam. For a certain type of wooden beam, Upper P equals StartFraction 8 comma 000 Over Upper D EndFraction
. What distance between supports is needed to carry 2000 lb?
For the beam to support a weight of 2000 lb, the distance between the supports needs to be no more than
enter your response here feet.
(Simplify your answer. Round to two decimal places as needed.)
1 answer
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